Calculator input and settings

Start here

Make the expression on the screen match the expression in the problem.

By the end of this section

Enter grouped expressions reliably; control signs, exponents, and angle units; use function notation; recognize stale definitions; and keep calculator work separate from the final answer field.

1.1 The permitted toolkit and the correct practice environment

Bluebook provides both Desmos graphing and scientific calculators during Math. A permitted, familiar handheld calculator is another option. Current SAT Suite policy prohibits calculators with CAS functionality and requires removal of stored documents and programs with algebra functionality. A model permitted for another exam is not automatically permitted for the SAT. Check the current policy before your administration.[1]

Use the graphing option for curves, intersections, functions, tables, and regression. Use the scientific option for numerical work when that layout is more comfortable. Desmos reports that entries in one calculator do not carry over into the other.[3] Do not switch expecting a function, table, or stored result to transfer.

The public Desmos website is useful for learning, but its latest features may not be enabled on the test. Select the SAT through the official testing page, then rehearse in Bluebook. Do not build a strategy around importing saved graphs, external links, or a new public-site feature.[4]

A setup routine you can explain

Check

Why it matters

Correct calculator

A numerical expression needs no graph; a system needs a graphical or algebraic method.

Clean workspace

Previous constants, functions, and tables can change the meaning of a new entry.

Angle unit

A number such as 30 is not automatically 30 degrees.

Cursor position

A new term may accidentally remain inside a denominator, root, or exponent.

Plausible result

A sign, scale, or unit check catches an entry error before it becomes a submitted answer.

What this guide does not ask you to learn

You do not need symbolic computer algebra, calculus, advanced probability-distribution commands, or a library of saved “hacks.” The useful core is small: correct arithmetic, function evaluation, graphing, tables, selected statistics, and regression when a model is appropriate.

Calculator availability is not a command to use it

For 4x = 28, division is sufficient. For 1.0837, numerical calculation can remove unnecessary arithmetic. The first decision is always mathematical: what operation or representation answers the actual question?

1.2 Grouping, templates, and the meaning of an entry

A calculator evaluates the structure you entered, not the structure you intended. A fraction bar groups its entire numerator and denominator. A radical groups everything under its bar. An exponent applies only to its base unless you create a larger group.

Intended expression

Build this entry

Inspect

a + bc + d

(a+b)/(c+d)

Both sums are grouped.

(−4)2

(-4)^2

The negative sign belongs to the base.

−42

-4^2

Squaring happens before the leading minus.

u + v

sqrt(u+v)

The entire sum is under the root.

93/2

9^(3/2)

The exponent is the fraction 3/2.

3.6 × 10−5

3.6*10^(-5)

The exponent is negative, not the coefficient.

Operate the cursor deliberately

Use the on-screen keypad or the keyboard to build a fraction, power, root, or function. After entering a denominator or exponent, move out of that template before adding the next term. Inspect the two-dimensional display after each risky step. Desmos documents keyboard access to fraction and root templates; device-specific shortcuts are supplementary, not a substitute for inspection.[7][23]

A useful spoken check: “the whole top, divided by the whole bottom.” For (8 + 4)/(5 − 2), the answer is 4. The different expression 8 + 4/5 − 2 is 6.8. Both are legal calculator entries, but only one represents the requested fraction.

Use explicit multiplication when clarity matters

Write 2*(x+3) or the visually equivalent 2(x + 3). For a substituted negative number, use parentheses: 5(−2), not an ambiguous run of signs. A decimal percent is a multiplier: 18% = 0.18. For an increase, multiply by 1.18; do not type “18” where the fraction 0.18 is needed.

Three different minus signs to notice

A negative base, a subtraction operation, and a negative exponent play different roles:

(−3)2 = 9, 7 − 32 = −2, 3−2 = 19.

Do not repair a surprising answer by randomly moving parentheses. Return to the intended mathematical expression and rebuild it.

1.3 Angle mode, functions, and clean definitions

Degrees and radians are different input units

For an angle described in degrees, choose degree mode before evaluating a trigonometric function. For a radian angle, choose radian mode. In the graphing calculator, the mode control is in Graph Settings.[6] Confirm the active setting instead of assuming a default.

sin(30°) = 12, sin(π/6) = 12.

These are the same angle in different units. In radian mode, sin(30) means the sine of 30 radians, not 30 degrees. A good mode check is a known value such as sin 30° or sin(π/6).

An inverse trigonometric function answers an angle question. If cos θ = 3/5 and θ is acute, use the inverse-cosine function to find θ. The notation cos−1 means inverse cosine in this context, not the reciprocal 1/cos.

Define once, then evaluate

In the graphing calculator, build f(x)=2*x^2-3*x+4. In a new expression, build f(-2). This evaluates the rule at x = −2; it does not solve an equation. Desmos supports reusing a defined function in later expressions and tables.[22]

Keep these three tasks separate:

Task

Meaning

f(3)

Input is known. Compute an output.

f(x) = 3

Output is known. Find the allowed input or inputs.

(3, f(3))

Plot the point whose input is 3 and output is f(3).

Old definitions are still definitions

Suppose an earlier problem set a = 4. A new entry y = ax + 1 uses that value of a; it does not know that your next question means a = 7. An old f(x) can cause a duplicate-definition error or evaluate the wrong rule. Remove or replace stale definitions and their dependent expressions when starting unrelated work.

A slider explores numerical choices for a constant. It does not prove that your chosen value is the only value satisfying a condition. For exact parameter questions, use an equation or an algebraic argument; see Example 2.15 and Example 3.14.

Display value versus stored value

Retyping a rounded decimal can throw away useful precision. When possible, evaluate a defined expression directly or keep the original exact fraction. A stored numerical result is still not a symbolic proof of an identity or an exact root.

1.4 Keep the calculator and the test interface distinct

A calculator expression is scratch work. It does not submit an answer to the question. After solving, return to the question and deliberately select an option or enter the requested number.

Bluebook provides a timer, Mark for Review, a question menu, an option eliminator, and access to a Math reference sheet. The calculator can be repositioned.[2] Practice using these controls without losing your place in the problem.

A screen-and-paper division of labor

Location

Best use

Question area

Read the target, qualifiers, units, answer choices, and response directions.

Scratch paper

Define variables; record restrictions; sketch; save a useful restart line.

Calculator

Carry out the chosen computation, show intersections, or evaluate a model.

Answer field

Record only the requested final response, in its required format.

Do not confuse three different actions

Eliminating an option records that you think it is wrong. Marking for review makes a question easier to find again. Selecting or entering an answer supplies the actual response. Make the third action explicit even when using the first two.

When the calculator covers part of a graph or a qualifier such as “positive,” move it or close it temporarily. Do not reconstruct hidden question text from memory. A perfect calculation for the wrong target is still the wrong response.

Practice a 90-second setup rehearsal

This is a training exercise, not a test-day rule. Open a Math question in a Bluebook preview. Locate the calculator and reference sheet. Move the calculator without changing its math window. Enter (9 + 3)/(5 − 1) and check that it equals 3. Find the angle-mode control. Return to the question, choose a response, mark it, and use the question menu to revisit it. Clear the practice work afterward.

A Bluebook test preview is untimed and gives no score or answer feedback; a signed-in full-length practice test provides scored practice. Use the preview for interface familiarity and a full test for a more realistic rehearsal.[16]

Your entry audit

Structure: Are the fraction, power, and root groups correct? State: Is the angle unit right, and are old definitions gone? Meaning: Does the output have a plausible sign and size? Transfer: Did the intended answer reach the question’s response field?

15 worked examples

1.01. Group the entire numerator and denominator

Evaluate 7 + 59 − 5.

Show worked solutionHide worked solution for example 1.01

Recognize. The fraction bar divides one whole sum by one whole difference. Both must stay grouped.

Enter: (7+5)/(9-5)

Work. The numerator is 12 and the denominator is 4, so the value is 12/4 = 3. After building the fraction, inspect the screen: 7 + 5 must be above the bar and 9 − 5 below it. An entry of 7 + 5/9 − 5 represents a different expression.

Answer: 3.

Check. Multiplying the result by the original denominator gives 3(9 − 5) = 12 = 7 + 5.

Avoid the trap. Do not trust a plausible decimal from an ungrouped entry. The denominator here is 4, not 9; reading the denominator aloud is a fast structural check.

1.02. Separate a negative base from a leading minus

Find the values of (−4)2 and −42, and explain why they differ.

Show worked solutionHide worked solution for example 1.02

Recognize. An exponent acts on its base before an ungrouped leading negative sign.

Enter: (-4)^2

Enter: -4^2

Work. The first expression squares the number −4: (−4)(−4) = 16. The second takes the negative of 42, giving −(16) = −16. Compare the displayed bases, not just the sequence of symbols. Parentheses change the mathematical object being squared.

Answer: 16 and −16, respectively.

Check. A square of a real number cannot be negative; the negative of a positive square is negative.

Avoid the trap. When substituting a negative value into x2, use parentheses around the value. Entering −42 does not perform the substitution x = −4 in x2.

1.03. Build a fraction inside a fraction

Evaluate 56 − 1478.

Show worked solutionHide worked solution for example 1.03

Recognize. The entire difference in the numerator is divided by 7/8.

Enter: (5/6-1/4)/(7/8)

Work. First, 5/6−1/4 = 10/12−3/12 = 7/12. Dividing by 7/8 multiplies by its reciprocal: (7/12)(8/7) = 2/3. The calculator may show a decimal approximation; the fraction calculation establishes the exact value.

Answer: 23.

Check. (2/3)(7/8) = 7/12, the original numerator. The answer should be slightly larger than 7/12 because the divisor is less than 1.

Avoid the trap. Leaving the cursor inside the first small denominator can place the subtraction under the wrong fraction bar. Reinspect the complete outer fraction before accepting the result.

1.04. Substitute a negative input safely

For x = −2, what is −3x2 + 5x?

Show worked solutionHide worked solution for example 1.04

Recognize. The input must be substituted into both occurrences of x, and the square comes before multiplication by −3.

Enter: -3*(-2)^2+5*(-2)

Work. Compute (−2)2 = 4, then −3(4) + 5(−2) = −12 − 10 = −22. The parentheses protect the negative input; they do not make the outside coefficient −3 part of the squared quantity.

Answer: −22.

Check. Both terms are negative: −3x2 = −12 and 5x = −10. A positive answer would signal a sign or grouping error.

Avoid the trap. The expressions (−3x)2 and −3x2 are different. Do not enlarge the base of the exponent while entering the substitution.

1.05. Keep a fractional exponent together

Evaluate 93/2.

Show worked solutionHide worked solution for example 1.05

Recognize. The exponent is the number 3/2, not 3 followed by division of the result by 2.

Enter: 9^(3/2)

Work. Because 9 is positive, 93/2 = (9)3 = 33 = 27. Inspect the display to confirm that the fraction 3/2 is entirely in the superscript. The different expression 93/2 equals 729/2.

Answer: 27.

Check. Alternatively, 93/2 = 99 = 9(3) = 27. Two equivalent exact forms agree.

Avoid the trap. Do not move out of the exponent template before completing its denominator. A familiar power pattern is also a useful check on the calculator entry.

1.06. Control scientific notation

Calculate 3.6 × 1051.2 × 10−3.

Show worked solutionHide worked solution for example 1.06

Recognize. Divide coefficients and subtract exponents. A very small denominator makes the result larger.

Enter: (3.6*10^5)/(1.2*10^(-3))

Work. The coefficient ratio is 3.6/1.2 = 3. The power ratio is 105−(−3) = 108. Thus the value is 3 × 108. A calculator may display scientific notation rather than all nine digits.

Answer: 3 × 108 = 300,000,000.

Check. Multiplying by the denominator gives (3 × 108)(1.2 × 10−3) = 3.6 × 105.

Avoid the trap. The negative sign belongs to the denominator's exponent. Writing −1.2 × 103 changes both the sign and magnitude. This is a calculation exercise, not an instruction to type scientific notation into an SPR field.

1.07. Translate successive percent changes before typing

A jacket priced at $240 is discounted by 15%. An 8% sales tax is then applied to the discounted price. What is the final price?

Show worked solutionHide worked solution for example 1.07

Recognize. Each percent acts on a specified base. Use a multiplier for each step.

Enter: 240*(1-0.15)*(1+0.08)

Work. The discount leaves 240(0.85) = 204. Tax then multiplies 204 by 1.08, giving 220.32. Building the whole expression keeps the order and bases visible, even though the two multiplicative factors commute.

Answer: $220.32.

Check. The tax is 0.08(204) = 16.32, and 204 + 16.32 = 220.32. The result lies between the discounted price and the original price.

Avoid the trap. Do not replace the two operations by a net 7% discount. The 15% reduction and 8% increase use different dollar bases.

1.08. Use the pi key rather than a short approximation

A circle has radius 7.5 centimeters. Find its area to the nearest tenth of a square centimeter.

Show worked solutionHide worked solution for example 1.08

Recognize. The radius is squared and then multiplied by π. Round only the final area.

Enter: pi*(7.5)^2

Work. A = πr2 = 56.25π ≈ 176.7145868. The hundredths digit is 1, so rounding to the nearest tenth gives 176.7. Keep π in the expression instead of replacing it with 3.14.

Answer: 176.7 cm2.

Check. Using 3 < π < 3.2 puts the area between 168.75 and 180, which contains the result.

Avoid the trap. An entry of (7.5π)2 incorrectly squares π as well. Confirm which factor is the base of the square.

1.09. Make the entire radicand visible

A right triangle has hypotenuse 13 and one leg 5. Find the other leg.

Show worked solutionHide worked solution for example 1.09

Recognize. The Pythagorean theorem gives a square root of a difference of squares, not a difference of lengths.

Enter: sqrt(13^2-5^2)

Work. If the missing leg is b, then b2 = 132 − 52 = 169 − 25 = 144. Therefore b = 12, using the positive root because a length is positive.

Answer: 12.

Check. 52 + 122 = 25 + 144 = 169 = 132.

Avoid the trap. Entering 132 − 52 leaves the subtraction outside the root. Entering 13 − 5 subtracts lengths instead of their squared values.

1.10. Diagnose the angle mode with a known value

A right triangle has hypotenuse 18 and an acute angle of 30°. Find the side opposite that angle.

Show worked solutionHide worked solution for example 1.10

Recognize. The opposite side is 18 sin 30°. The degree symbol determines the input unit.

Enter: 18*sin(30)

Work. Select degree mode before evaluating. Since sin 30° = 1/2, the expression equals 18(1/2) = 9. A negative output from this entry is a warning that the angle was interpreted in radians or that another input error occurred.

Answer: 9.

Check. A 30°–60°–90° triangle has its short leg equal to half its hypotenuse. The exact triangle relationship confirms the calculation.

Avoid the trap. Do not take the absolute value of a wrong-mode output to make it look like a length. Repair the unit setting, then recompute.

1.11. Use inverse cosine for an angle

For an acute angle θ, cos θ = 3/5. Find θ in degrees, to the nearest tenth.

Show worked solutionHide worked solution for example 1.11

Recognize. The ratio is known and the angle is unknown. This is an inverse-function task.

Work. Select degree mode and choose the inverse-cosine function from the function keypad. Build cos−1(3/5). The angle is approximately 53.130102°, which rounds to 53.1°. In radian mode, the same inverse operation returns approximately 0.927295, a different unit for the same angle.

Answer: 53.1°.

Check. cos(53.130102°) ≈ 0.6, which matches 3/5. The angle is between 0° and 90° as required.

Avoid the trap. Use the actual inverse-cosine function, not 1/cos(3/5). Also do not relabel a radian output as degrees without conversion.

1.12. Evaluate a defined function instead of retyping

Let f(x) = 2x2 − 3x + 4. What is f(−2)?

Show worked solutionHide worked solution for example 1.12

Recognize. The question supplies an input. A function definition lets you reuse the rule without recopying it.

Enter: f(x)=2*x^2-3*x+4

Enter: f(-2)

Work. The second line evaluates the first line at x = −2. Algebra gives 2(−2)2 − 3(−2) + 4 = 8 + 6 + 4 = 18. The displayed value is an output, not a solution of f(x) = −2.

Answer: 18.

Check. The three evaluated terms are 8, 6, and 4; their sum is 18. This check also catches an omitted negative sign.

Avoid the trap. A leftover definition of f can invalidate the setup. Begin with the function named in this question, and use a new expression line for its evaluation.

1.13. Enter a difference quotient without changing its scope

For f(x) = x2, evaluate f (3.01) − f (3)0.01.

Show worked solutionHide worked solution for example 1.13

Recognize. The numerator is a difference of two outputs. The denominator divides that entire difference.

Enter: (3.01^2-3^2)/0.01

Work. 3.012 = 9.0601, so the numerator is 0.0601. Dividing by 0.01 gives 6.01. You could instead define f(x) = x2 and enter ( f(3.01) − f(3))/0.01. Neither method requires calculus.

Answer: 6.01.

Check. Use difference of squares: (3.012 − 32)/(3.01 − 3) = 3.01 + 3 = 6.01. This exact identity avoids subtracting nearby rounded displays.

Avoid the trap. An entry of f(3.01) − f(3)/0.01 divides only the second output. Keep the whole difference over the denominator.

1.14. Remove stale parameter values

An earlier calculation defined a = 4. A new problem defines f(x) = 7x + 1 and asks for f(3). A student enters f(x) = ax + 1 and obtains 13. Diagnose and correct the error.

Show worked solutionHide worked solution for example 1.14

Recognize. The software is applying an old definition correctly to the wrong new model.

Enter: f(x)=7*x+1

Enter: f(3)

Work. Remove or replace the obsolete function entry. Use the stated coefficient 7 explicitly, or deliberately redefine a = 7 and confirm all dependent expressions. The requested output is 7(3) + 1 = 22. The earlier output 4(3) + 1 = 13 reveals exactly which value was used.

Answer: 22; the error was a stale value of a.

Check. The new function has f(0) = 1 and increases by 7 for each unit increase in input. From input 0 to 3, its output rises by 21.

Avoid the trap. An ordinary calculator cannot infer that a new question has begun. Hiding a curve without clearing its definitions may leave hidden dependencies.

1.15. Audit a complete multi-template expression

Evaluate (−3)2 + 492(1 + 3) and identify the entry decisions that protect its meaning.

Show worked solutionHide worked solution for example 1.15

Recognize. This calculation combines a negative base, a root, a sum, and a product in a denominator.

Enter: ((-3)^2+sqrt(49))/(2*(1+3))

Work. Build the numerator first: the square is 9 and the root is 7, giving 16. Build the complete denominator separately: 2(1+3) = 2(4) = 8. The fraction is therefore 16/8 = 2. Inspect the final display before evaluating: the numerator is not merely 49, and the factor 2 belongs below the fraction bar.

Answer: 2.

Check. Multiplying 2 by the full denominator gives 16, exactly the full numerator. The answer is positive because both numerator and denominator are positive.

Avoid the trap. Four edits can each change the problem: omitting the parentheses around −3; extending the radical too far; leaving 2 outside the denominator; or leaving +3 outside the denominator's parentheses. Repair the structure, not the final decimal.

A component-by-component audit

Component

Exact structure

Value

Negative base squared

(−3)(−3)

9

Principal square root

49

7

Entire numerator

9 + 7

16

Entire denominator

2(1 + 3)

8

Final quotient

16/8

2

Transfer habit

When a long entry fails, inspect one mathematical component at a time. Repeatedly typing the whole expression without identifying its structure can reproduce the same mistake.

Section synthesis: inspect the expression tree

Before evaluating, identify the outermost operation. Then inspect its groups from the outside inward: whole numerator and denominator, base and exponent, radicand, function input. Finally check active definitions and units. This routine protects the mathematics before any digits appear.

1.6 Section exit check

Work without the lesson open. Choose a method, show enough reasoning to check the result, and record any tool or interpretation error. These questions include tool-decision drills as well as mathematical problems.

Topic practice

Before checking the solutions

Name one question where a manual method was shorter, one place where calculator setup needed care, and one check that would catch a plausible wrong answer. If you cannot name an independent check, return to the relevant worked example.