Try each question before choosing Check answer. Guide question labels stay the same when you shuffle the bank. 4 written responses appear below the bank, with model answers for self-review; these are not automatically graded. Follow any rounding instruction in the question.
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Compare the reasoning as well as the answer. Equivalent valid methods are welcome. A referenced example provides a targeted repair route.
The drill
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Question 2
Guide question E1.2
Find the value of −2x2 + 4x when x = −3.
Enter an integer, decimal or fraction without units. Use up to 5 characters, or 6 including a leading minus.
Why this answer
−30.
Substitute with grouped negatives: −2(−3)2 + 4(−3) = −2(9) − 12 = −30. One entry is -2*(-3)^2+4*(-3). The leading −2 is a coefficient, not part of the squared base. A result such as 24 or 6 signals that the sign or grouping changed. Review Example 1.04.
Write your complete response before opening the model answer. Compare both your answer and your reasoning.
Guide question E1.1
Evaluate . Write a calculator entry that preserves the intended grouping.
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4.
Use (9+7)/(6-2). The numerator is 16 and the denominator is 4, so the quotient is 4. The entry 9+7/6-2 would mean something different because only 7 would be divided by 6. A quick exact calculation checks that the display matches the fraction. Review Example 1.01.
Guide question E1.3
A right triangle has hypotenuse 20. What is the length of the side opposite a 30° angle? Identify the angle setting needed for a numerical sine calculation.
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10; degrees.
The side is 20 sin 30° = 20(1/2) = 10. With the calculator in degree mode, use 20*sin(30). The special-triangle relationship provides an independent check: the side opposite 30° is half the hypotenuse. A radian-mode calculation of sin(30) would represent a different angle. Review Example 1.10.
Guide question E1.4
Let f(x) = 3x2 − x + 2. Find f(−2) and give a reusable function-entry method.
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16.
Define f(x)=3*x^2-x+2, then evaluate f(-2). Algebra confirms 3(4) − (−2) + 2 = 12 + 2 + 2 = 16. The minus sign before x becomes addition when a negative input is substituted. A function definition is useful when several evaluations are needed, but direct substitution is equally valid for one input. Review Example 1.12.
Guide question E1.5
An old calculator entry defines m = 3. A new problem requires y = mx + 5 with m = −2. What should y be at x = 4, and what must be corrected before relying on the calculator?
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−3; replace or remove the old definition.
The new relationship is y = −2x + 5, giving y = −8 + 5 = −3. Replace the stored assignment m = 3 with m = −2, or enter the new equation directly with its numerical coefficient. The old value would produce 17, a correct output for the wrong model. Inspect definitions rather than treating every display as independent of earlier work. Review Example 1.14.