Problem-Solving and Data Analysis — Topic practice
12 exercises · 12 automatically checked · Untimed
Instructions and review guidance
12 questions · Shuffled order · Untimed practice
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Question 1
Guide question P-D01
Standard
A recipe uses flour and sugar in the ratio 7 : 3. If it uses 420 grams of flour, how many grams of sugar does it use?
Enter an integer, decimal or fraction without units. Use up to 5 characters, or 6 including a leading minus.
Why this answer
Answer: 180 The scale factor is 420/7 = 60 grams per ratio part. Sugar is 3 parts, so 3(60) = 180 grams.
Ratios and proportions / Standard Review: Data reference.
The dot plot shows seven observations. What is their median?
Why this answer
Answer: B / 4 The ordered observations are 1, 2, 2, 4, 4, 4, 7. The fourth observation, the middle of seven, is 4. Dot height gives frequency, not a separate data value.
Every value in a data set is multiplied by 3. Which statement must be true?
Why this answer
Answer: A / The standard deviation is multiplied by 3. Multiplying all values by positive 3 multiplies the mean and every deviation from that mean by 3. Hence the standard deviation also triples.
Spread and transformations / Standard Review: Example 2.11.
A bag contains 5 green and 7 yellow counters. Two are selected without replacement. What is the probability that both are green?
Enter an integer, decimal or fraction without units. Use up to 5 characters, or 6 including a leading minus.
Why this answer
Answer: 5/33 The first-green probability is 5/12. After a green is removed, 4 green counters remain among 11 counters. Multiply: (5/12)(4/11) = 20/132 = 5/33.
Probability without replacement / Challenge Review: Example 6.14.
In a random sample of 200 residents, 74 support a proposal. Using this sample, estimate the number of supporters among 5000 residents.
Enter an integer, decimal or fraction without units. Use up to 5 characters, or 6 including a leading minus.
Why this answer
Answer: 1850 The sample rate is 74/200 = 0.37. Multiply by 5000 to estimate 1850 supporters. Random sampling does not make the estimate an exact count.
Population inference / Standard Review: Example 2.15.
A random sample of a town is surveyed about exercise and sleep. An association is found. Which conclusion is justified by the design alone?
Why this answer
Answer: C / The sample can inform an association estimate for the town, but not a causal conclusion. Random sampling supports generalization to the sampled population, with uncertainty. Without randomized treatment assignment, the association does not establish causation.