Mixed-topic practice

Use the guidance first, attempt each worked example, then open its solution. Practice sets and timed rehearsals keep their original boundaries.

2.1 Make the first decision visible

A chapter heading can quietly choose your method for you. In mixed practice, begin by writing a short statement of the target and a plausible first step. This reveals whether a miss came from selecting a model, executing it, or interpreting the result.

What you notice First question to ask

A graph, table, or story Which quantities vary, and what is the requested input, output, or comparison?

A repeated expression Can it be treated as one object or related directly to the target?

Two equations Would adding, subtracting, substituting, or graphing expose the target?

A percent, rate, or scale What is the base, interval, or unit, and is it changing?

A parameter or Can the equation change degree? Are any candidate inputs excluded? solution count

A statistical claim What does the data collection justify, and what uncertainty remains?

2.2 Use two different passes

On the first pass, solve with the reference closed except for the standard Reference control if you are rehearsing test conditions. On the review pass, identify the clue you used, compare the explanation, and decide whether another route would have been simpler for this item. The 30 independent mixed questions are split into two 15-question sets. Topic and difficulty labels appear only in their explanations. No time limit is mandatory for these sets. Start untimed if method selection is still uncertain; add a timer only when you have a defensible method to execute.

Do not confuse a different method with a wrong method A valid alternative deserves credit even if it differs from the worked solution. Check whether it preserves the original conditions, finds the requested quantity, and verifies the result. Then compare reliability and time. The shortest-looking method is not always the easiest one to execute accurately.

15 worked examples

2.01. Begin with the requested output

For all real x, f(x) = ax + b. If f(3) = 14 and f(8) = 34, what is f (11)?

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Work. The output rises 20 while the input rises 5, so the slope is 4. From input 8 to 11, add 3(4) = 12 to the output: f (11) = 34 + 12 = 46. Finding b = 2 is optional.

Answer: 46

Check. The rule f(x) = 4x + 2 fits both given pairs.

Key takeaway. The decisive clue is a constant rate of change, not the presence of function notation.

2.02. Treat successive changes as one relationship

A price is increased by 25% and then reduced by 20%. The final price is $84. What was the original price?

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Work. The two multipliers are 1.25 and 0.80. Their product is 1, so the final price equals the original price. Equivalently, p(1.25)(0.80) = 84 gives p = 84.

Answer: $84

Check. 84 → 105 → 84. The percentages use different bases.

Key takeaway. Equal-looking percentages are not added; compose the multipliers.

2.03. Connect geometry to a quadratic model

A rectangle has width x and length x + 5. Its area is 84. What is its perimeter?

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Work. The area equation is x(x + 5) = 84, so x2 + 5x − 84 = (x + 12)(x − 7) = 0. A positive width requires x = 7. The length is 12 and the perimeter is 2(7 + 12) = 38.

Answer: 38

Check. 7 · 12 = 84. The negative candidate −12 cannot be a length.

Key takeaway. A quadratic root is an intermediate result when the question asks for perimeter.

2.04. Use an equation combination to reach the target

If 4x + 3y = 29 and 2x − 3y = 1, what is 6x?

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Work. Adding the equations eliminates y and produces 6x = 30 immediately. There is no need to compute x = 5 unless using it to check the result.

Answer: 30

Check. x = 5 gives y = 3 in either original equation.

Key takeaway. Compare the requested expression with sums, differences, and multiples of the given equations.

2.05. Read an exponential pattern from two values

A positive exponential function g satisfies g(1) = 10 and g(4) = 80. What is g(6)?

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Work. The factor over 3 input units is 80/10 = 8. A positive one-unit base therefore satisfies b3 = 8, so b = 2. Two more input units multiply the value by 22 = 4: g(6) = 320.

Answer: 320

Check. The rule g(x) = 5 · 2x reproduces both given values.

Key takeaway. For exponential models, compare ratios over equal input intervals rather than differences.

2.06. Translate a percentage constraint into an inequality

A batch contains 18 defective items and an unknown number of nondefective items. What is the least total batch size for which at most 6% of the items are defective?

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Work. Let the total be n > 0. The condition is 18/n ≤ 0.06. Multiplying by positive n gives 18 ≤ 0.06n, so n ≥ 300. Thus the least total is 300.

Answer: 300

Check. 18/300 = 0.06; any smaller positive total gives a larger defective fraction.

Key takeaway. Identify whether the variable is a part or the whole. Here 300 is the total, not the number of nondefective items.

2.07. Exploit symmetry instead of expanding

The quadratic f(x) = (x − 6)2 + 4 satisfies f (a) = f (10). If a ≠ 10, find a.

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Work. The axis of symmetry is x = 6. Input 10 is 4 units to the right, so the other input is 4 units to the left: a = 2. Algebraically, (a − 6)2 = 16 gives a = 10 or 2.

Answer: 2

Check. f(2) = f (10) = 20.

Key takeaway. Equal quadratic outputs occur at inputs equally spaced from the axis, unless the two inputs coincide.

2.08. Read conditional information from a table

A survey records 50 bicycle commuters and 70 other commuters. Of the bicycle commuters, 35 support a bike lane; of the other commuters, 28 support it. A supporter is selected at random. What is the probability that the person is a bicycle commuter?

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Work. The selected population contains only supporters, of whom there are 35 + 28 = 63. Among them, 35 are bicycle commuters. The probability is 35/63 = 5/9.

Answer: 59

Check. 35/50 answers a different question: support given bicycle commuting.

Key takeaway. Reverse conditioning usually changes the denominator; the two conditional probabilities need not be equal.

2.09. Determine what an intercept means

The model P = 480 − 12t gives the number of pages remaining after t hours of scanning. What does the t-intercept represent?

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Work. At the t-intercept, P = 0. Solve 480 − 12t = 0 to get t = 40. In context, this is the predicted number of hours needed to finish scanning the pages.

Answer: 40 hours, when no pages remain.

Check. The rate has units pages per hour, so 480 pages/(12 pages/hour) = 40 hours.

Key takeaway. An intercept is not merely a coordinate to compute; its interpretation depends on which variable is zero.

2.10. Connect a line and a circle

The circle (x − 2)2 + (y + 1)2 = 25 meets the horizontal line y = 3 at two points. What is the distance between them?

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Work. Substitute y = 3: (x − 2)2 + 16 = 25, so (x − 2)2 = 9. Thus the intersections have x = −1 and x = 5, both with y = 3. Their horizontal separation is 5 − (−1) = 6.

Answer: 6

Check. The chord is 4 units from the center of a radius-5 circle; its half-length is 25 − 16 = 3.

Key takeaway. The requested distance can be simpler than a full system solution.

2.11. Compare variability by structure

Data set A is {2, 4, 6, 8} and data set B is {12, 16, 20, 24}. What is the ratio of the standard deviation of B to that of A?

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Work. Each B value is obtained by multiplying its corresponding A value by 2 and adding 8. Addition does not change spread; multiplication by 2 doubles every deviation from the mean. The ratio is 2.

Answer: 2

Check. The means are 5 and 18. Deviations (−3, −1, 1, 3) become (−6, −2, 2, 6).

Key takeaway. Compare transformations before calculating a standard deviation from scratch.

2.12. Keep a parameter exception visible

For what value of k does (k − 3)x = 2k + 1 have no solution?

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Work. A nonzero coefficient of x yields one solution. No solution is possible when k − 3 = 0 but the right side is nonzero. At k = 3, the equation becomes 0 = 7, a contradiction.

Answer: k = 3

Check. For every other k, x = (2k + 1)/(k − 3) exists.

Key takeaway. Before dividing by an expression containing a parameter, test when that expression is zero.

2.13. Convert area units with the squared factor

A sheet has area 0.72 m2. What is its area in square centimeters?

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Work. Since 1 m = 100 cm, an area conversion uses 1002 = 10,000. Thus 0.72 m2 = 7200 cm2.

Answer: 7200 cm2

Check. A 0.8 m by 0.9 m sheet has the same area as an 80 cm by 90 cm sheet.

Key takeaway. The exponent on a unit applies to the conversion factor too.

2.14. Locate the hidden quadratic condition

The line y = 4x + c is tangent to the parabola y = x2 − 2x + 7. Find c.

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Work. Equating outputs gives x2 − 6x + 7 − c = 0. Tangency requires one repeated real root, so (−6)2 − 4(7 − c) = 0. Hence 36 − 28 + 4c = 0, and c = −2.

Answer: −2

Check. At c = −2, the intersection equation is (x − 3)2 = 0; both graphs meet at (3, 10).

Key takeaway. Tangency is a solution-count statement. A graph can suggest it; a repeated-root calculation verifies it.

2.15. Separate a population estimate from a guarantee

In a random sample of 250 members of a 6000-member organization, 90 prefer a new schedule. Estimate how many members prefer it.

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Work. The sample proportion is 90/250 = 0.36. Apply that rate to the population: 6000(0.36) = 2160. This is an estimate, not a known exact count.

Answer: An estimated 2160 members.

Check. The estimated count is between 0 and 6000 and corresponds to 36% of the population.

Key takeaway. Inference requires an appropriate sampling process and retains uncertainty even when the arithmetic is exact.

2.4 Mixed set 1

Work with solutions closed. Use separate scratch paper when needed. Record confidence and help used before reviewing.

Open mixed practice

2.5 Mixed set 2

Work with solutions closed. Use separate scratch paper when needed. Record confidence and help used before reviewing.

Open mixed practice