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Practice explanations
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Question 1
Guide question E2.1
For all real x, which expression equals (x + 2)2 − x2?
Why this answer
B,4x + 4
Expand only the needed square: (x + 2)2 − x2 = x2 + 4x + 4 − x2= 4x + 4. A useful choice test is x = 2: the target is 16 − 4 = 12, while A, C, and D give 4, 8, and 8. That single input eliminates all three competitors; the expansion proves the identity. See Example 2.07.
After a 15% discount, an item costs $68. What was the original price?
Why this answer
C, $80
An original price P becomes 0.85P = 68 after a 15% discount. Thus P = 68/0.85 = 80. Alternatively, test 80 in the original process: 15% of 80 is 12, and 80 − 12 = 68. Adding 15% to 68 does not undo the discount because the percentage base has changed. See Example 2.04.
Positive a and b satisfy a = 4b. Find (a + b)/(a − b).
Enter an integer, decimal or fraction without units. Use up to 5 characters, or 6 including a leading minus.
Why this answer
5/3
Since a = 4b, substitute to get (a + b)/(a − b) = 5b/(3b) = 5/3. The positive-value condition ensures b ≠ 0. For candidate testing, b = 1 and a = 4 satisfy the relationship and give the same ratio. Choosing a and b independently would ignore the most important condition. See Example 2.08.
The identity (x − 3)(ax + b) = 2x2 − 5x − 3 holds for all real x. Find a + b without first finding both constants separately.
Enter an integer, decimal or fraction without units. Use up to 5 characters, or 6 including a leading minus.
Why this answer
3
Because the identity holds for every real input, choose x = 1 to create the requested group: −2(a + b) = 2 − 5 − 3 = −6. Thus a + b = 3. A coefficient check gives a = 2 and b = 1, and (x − 3)(2x + 1) = 2x2 − 5x − 3. Substituting x = 3 produces 0 = 0, which is true but gives no information about the target. See Example 2.15.
Write your complete response before opening the model answer. Compare both your answer and your reasoning.
Guide question E2.4
A student tests x = 1 to decide whether x2 = x holds for every real x. The test succeeds. Give an allowed counterexample, and state what it proves.
Show model answerHide model answer for question E2.4
For example,x = 2
At x = 2, the claimed equality becomes 4 = 2, which is false. One valid counterexample disproves a statement asserted for every real x. Testing x = 1 only shows that the equality holds at that input; it does not establish an identity. In fact, x2= x holds only when x(x − 1) = 0, so only at 0 and 1. See Example 2.12.