Work through the set before checking solutions. Guide question labels match the source lesson references. 2 written responses appear below the question bank, with model answers for self-review; these are not automatically graded.
Guide question labels stay the same when the order changes. Check answers when you are ready to review.
Written self-checks are below the question bank and are excluded from the automatic score.
Written responses are self-review exercises.
Saved on this browser and device; clearing browser data removes progress.
The drill
Your practice is saved on this device.
Question 2
Guide question E5.2
If Q(t) = 72 ⋅ 3t/4, find Q(8).
Enter an integer, decimal or fraction without units. Use up to 5 characters, or 6 including a leading minus.
Why this answer
648
In Q(t) = 72 ⋅ 3t/4, every 4-unit interval contributes a factor of 3. At t = 8, two such intervals have elapsed:
Q(8) = 72 ⋅ 38/4= 72 ⋅ 9 = 648.
The exponent counts the number of growth periods, not the absolute time value. Review 5.03.
An exponential function f(t) = Abt, with A, b > 0, satisfies f(1) = 10 and f(3) = 40. Find f(0).
Enter an integer, decimal or fraction without units. Use up to 5 characters, or 6 including a leading minus.
Why this answer
f(0) = 5
Divide the equations Ab3= 40 and Ab = 10:
b2 = = 4.
The given condition b > 0 selects b = 2. Then A = 10/2 = 5, so f(0) = A = 5. Check: 5(2)3= 40. The two-unit interval has a factor of 4; the one-unit factor is 2. Review 5.06.
An amount increases by 25% and then decreases by 20%. What is the combined multiplier?
Enter an integer, decimal or fraction without units. Use up to 5 characters, or 6 including a leading minus.
Why this answer
Combined multiplier 1
The successive multipliers are 1.25 and 0.80, so the combined multiplier is 1.25(0.80) = 1. The final amount equals the initial amount. The second change is calculated from a different base, so adding the signed percentages, 25% − 20%, does not give the net change. Review the multiplier lesson and 5.09.
Write your complete response before opening the model answer. Compare both your answer and your reasoning.
Guide question E5.1
Write a model for an initial amount of 900 that decreases by 15% each year.
Show model answerHide model answer for question E5.1
P(t) = 900(0.85)t
A 15% decrease leaves 100% − 15% = 85% of the previous amount each year. The yearly multiplier is 0.85, and the initial value is 900. Thus P(t) = 900(0.85)t for time t in years. The base is the fraction remaining, not the fraction lost. Review 5.02.
Guide question E5.4
In P(t) = 500(1.10)t/2, with t in years, what is the exact annual growth factor?
Show model answerHide model answer for question E5.4
Rewrite 500(1.10)t/2= 500 ((1.10)1/2)t.
Thus the annual multiplier is , approximately 1.04881. The annual percentage increase is approximately 4.88%, but the question asks for the factor. Dividing 10% by 2 is not exact compound-growth reasoning. Review 5.07.